DIVIDER CIRCUITS AND KIRCHHOFF'S LAWS
Voltage divider circuits
Let's analyze a simple series circuit, determining the voltage drops across individual resistors:From the given values of individual resistances, we can determine a total circuit resistance, knowing that resistances add in series:
From here, we can use Ohm's Law (I=E/R) to determine the total current, which we know will be the same as each resistor current, currents being equal in all parts of a series circuit:
Now, knowing that the circuit current is 2 mA, we can use Ohm's Law (E=IR) to calculate voltage across each resistor:
It should be apparent that the voltage drop across each resistor is proportional to its resistance, given that the current is the same through all resistors. Notice how the voltage across R2 is double that of the voltage across R1, just as the resistance of R2 is double that of R1.
If we were to change the total voltage, we would find this proportionality of voltage drops remains constant:
The voltage across R2 is still exactly twice that of R1's drop, despite the fact that the source voltage has changed. The proportionality of voltage drops (ratio of one to another) is strictly a function of resistance values...............................................
